One of the problem building a robot is the choice of motors. I’m speaking about a mobile robot with wheel. So, I’m not speaking about legs or others geometries.

A simple robot with 2 wheel that goes around in the house. So a robot moving on a flat surface, no hills. Without tracks, without rough terrain. No SUV!

In this situation the calculations are complex and out of the aim of this little tutorial for beginners.

First we can start from the value usually reported in any motor datasheet: the torque. The torque is, in the rotation, the equivalent of force in the linear motion. To push a box, bigger it is the force, bigger it is the acceleration. For a wheel, bigger it is the torque, bigger it is the wheel acceleration (rotational).

In the datasheets often it speaks about stall torque (*start-up torque, stall torque)* and, somethimes, about nominal torque (*rated torque*).

The start-up torque is the maximum torque that the motor can provide. But when the motor is in stall, the motor is stopped. So it isn’t very useful. It would be useful to have the rated torque, that is, (approximately) the maximum torque that ensures continous operation of the engine, without problems.

If the rated torque is not present in the datasheet, we can consider the first formula (approximated):

**Rated torque=star-up torque / 2**

Now, we can consider the robot motion formulas. There is a formula that links the motor torque with the robot weight and acceleration. So this formula provides us a very important information. That is, knowing the robot weight (in kg), knowing the acceleration desired, this formulas says wich is the torque that we have to consider in the motor choice.

Some information are required:

– robot mass (you can put the robot in a balance and read the weight in kg).

– the wheels radius (in cm.). Please note that the radius is half the diameter

– the robot acceleration desired. For example, 0.5 m/s^2. This means that we start the robot motion, after 2 seconds it will have a speed of *v=a*t=0.5*2=1 m/s*, i.e. a meter for each second. Not so bad for a home robot.

The motion formula is:

**C/r=m*a + Fattr**

where: * C* is the rated torque of the motor,

*is the wheel radius,*

**r***is the mass,*

**m***is the acceleration and*

**a***is the attrition force (here mostly rolling) between the wheel and the floor.*

**Fattr**The

*is complicated. We can do a semplification:*

**Fattr****Fattr=m*a**

Basically, when we have to calculate the torque, we can double the torque deriving from the *m*a* calcolation. Maybe, this could be a conservative calculation, but we can be serene in the motor choice.

So let’s recap:

**C/r=2*m*a**

We must consider that the robot is pushed by two engines, the right one and the left one, so we just need half torque. The formula becames:

**C/r=m*a –> C=m*a*r**

Let’s take an example. Suppose you have a little robot that weights 2 kg, with two wheels with 8 cm diameter (4 cm radius) and we want an acceleration of 0.5 m/s^2. You get:

*C=2*0,5*4=4 N*cm.*

So the engine should have a 4 N*m torque. The motors often have a torque indicated in kg*cm. So we have to divide by 9.81 (approximately 10).

So you get a motor with a rated torque of 0.4 kg*cm, and 0.8 kg*cm of start-up torque. Easy or not?

Now consider the speed. Suppose we want a robot whit 1 m/s of speed, that means 3.6 km/h.

If the wheel has a 4 cm radius, the distance traveled at each revolution is:

*d=2*pi*r = 6.28 * 4 = 25.12 cm*

So, to make 1 meter per second:

*100/25.12 revolution per second = 3.98 revolution per second.*

knowing that in a minute there are 60 seconds, you get the revolutions per minute (rpm), another data often written in a motor datasheet.

*rpm = revolutions per second * 60** = 3.98 * 60 = 239 rpm*

With the data of torque and the rpm we are able to choose the right motor.

All the formulas are simplified, however, it is enough for beginners and for DIY robot builders!

#1 by

Kabeeron 19 September 2018 - 14:31Quote

I have a small doubt. You considered the driving force of the model as ‘ma’. This is fine but what about the frictional force that we have to overcome.

shouldn`t there be a mg*friction term in there.

#2 by Ravi shokeen on 7 December 2017 - 09:34

Quote

If i want to make a robot having 4 wheels

who can lift 20 kg of total load

Then please suggest what kind of wheels(size) and motor(rpm & torque)

should i use if

The speed is to be around 10cm/second

Please provide information

#3 by

Rehanon 3 October 2017 - 05:04Quote

Been trying to find a clear explaination and relation between the weight of the robot and the torque of the motor and finally found it in your website!

Thanks a lot!

#4 by Ravi shokeen on 7 December 2017 - 09:35

Quote

If i want to make a robot having 4 wheels

who can lift 20 kg of total load

Then please suggest what kind of wheels(size) and motor(rpm & torque)

should i use if

The speed is to be around 10cm/second

Please provide information